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0587dd17 WD |
1 | /* |
2 | * (C) Copyright 2001 | |
3 | * Wolfgang Denk, DENX Software Engineering, [email protected]. | |
4 | * | |
1a459660 | 5 | * SPDX-License-Identifier: GPL-2.0+ |
0587dd17 WD |
6 | */ |
7 | ||
8 | /* | |
9 | * Date & Time support for Philips PCF8563 RTC | |
10 | */ | |
11 | ||
12 | #include <common.h> | |
13 | #include <command.h> | |
14 | #include <rtc.h> | |
15 | ||
a593814f | 16 | #if defined(CONFIG_CMD_DATE) || defined(CONFIG_TIMESTAMP) |
0587dd17 WD |
17 | |
18 | #define FEBRUARY 2 | |
19 | #define STARTOFTIME 1970 | |
20 | #define SECDAY 86400L | |
21 | #define SECYR (SECDAY * 365) | |
22 | #define leapyear(year) ((year) % 4 == 0) | |
53677ef1 WD |
23 | #define days_in_year(a) (leapyear(a) ? 366 : 365) |
24 | #define days_in_month(a) (month_days[(a) - 1]) | |
0587dd17 WD |
25 | |
26 | static int month_days[12] = { | |
27 | 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 | |
28 | }; | |
29 | ||
30 | /* | |
31 | * This only works for the Gregorian calendar - i.e. after 1752 (in the UK) | |
32 | */ | |
33 | void GregorianDay(struct rtc_time * tm) | |
34 | { | |
35 | int leapsToDate; | |
36 | int lastYear; | |
37 | int day; | |
38 | int MonthOffset[] = { 0,31,59,90,120,151,181,212,243,273,304,334 }; | |
39 | ||
40 | lastYear=tm->tm_year-1; | |
41 | ||
42 | /* | |
43 | * Number of leap corrections to apply up to end of last year | |
44 | */ | |
45 | leapsToDate = lastYear/4 - lastYear/100 + lastYear/400; | |
46 | ||
47 | /* | |
48 | * This year is a leap year if it is divisible by 4 except when it is | |
49 | * divisible by 100 unless it is divisible by 400 | |
50 | * | |
51 | * e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 will be | |
52 | */ | |
53 | if((tm->tm_year%4==0) && | |
54 | ((tm->tm_year%100!=0) || (tm->tm_year%400==0)) && | |
55 | (tm->tm_mon>2)) { | |
56 | /* | |
57 | * We are past Feb. 29 in a leap year | |
58 | */ | |
59 | day=1; | |
60 | } else { | |
61 | day=0; | |
62 | } | |
63 | ||
64 | day += lastYear*365 + leapsToDate + MonthOffset[tm->tm_mon-1] + tm->tm_mday; | |
65 | ||
66 | tm->tm_wday=day%7; | |
67 | } | |
68 | ||
69 | void to_tm(int tim, struct rtc_time * tm) | |
70 | { | |
71 | register int i; | |
72 | register long hms, day; | |
73 | ||
74 | day = tim / SECDAY; | |
75 | hms = tim % SECDAY; | |
76 | ||
77 | /* Hours, minutes, seconds are easy */ | |
78 | tm->tm_hour = hms / 3600; | |
79 | tm->tm_min = (hms % 3600) / 60; | |
80 | tm->tm_sec = (hms % 3600) % 60; | |
81 | ||
82 | /* Number of years in days */ | |
83 | for (i = STARTOFTIME; day >= days_in_year(i); i++) { | |
84 | day -= days_in_year(i); | |
85 | } | |
86 | tm->tm_year = i; | |
87 | ||
88 | /* Number of months in days left */ | |
89 | if (leapyear(tm->tm_year)) { | |
90 | days_in_month(FEBRUARY) = 29; | |
91 | } | |
92 | for (i = 1; day >= days_in_month(i); i++) { | |
93 | day -= days_in_month(i); | |
94 | } | |
95 | days_in_month(FEBRUARY) = 28; | |
96 | tm->tm_mon = i; | |
97 | ||
98 | /* Days are what is left over (+1) from all that. */ | |
99 | tm->tm_mday = day + 1; | |
100 | ||
101 | /* | |
102 | * Determine the day of week | |
103 | */ | |
104 | GregorianDay(tm); | |
105 | } | |
106 | ||
107 | /* Converts Gregorian date to seconds since 1970-01-01 00:00:00. | |
108 | * Assumes input in normal date format, i.e. 1980-12-31 23:59:59 | |
109 | * => year=1980, mon=12, day=31, hour=23, min=59, sec=59. | |
110 | * | |
111 | * [For the Julian calendar (which was used in Russia before 1917, | |
112 | * Britain & colonies before 1752, anywhere else before 1582, | |
113 | * and is still in use by some communities) leave out the | |
114 | * -year/100+year/400 terms, and add 10.] | |
115 | * | |
116 | * This algorithm was first published by Gauss (I think). | |
117 | * | |
118 | * WARNING: this function will overflow on 2106-02-07 06:28:16 on | |
119 | * machines were long is 32-bit! (However, as time_t is signed, we | |
120 | * will already get problems at other places on 2038-01-19 03:14:08) | |
121 | */ | |
122 | unsigned long | |
123 | mktime (unsigned int year, unsigned int mon, | |
124 | unsigned int day, unsigned int hour, | |
125 | unsigned int min, unsigned int sec) | |
126 | { | |
127 | if (0 >= (int) (mon -= 2)) { /* 1..12 -> 11,12,1..10 */ | |
128 | mon += 12; /* Puts Feb last since it has leap day */ | |
129 | year -= 1; | |
130 | } | |
131 | ||
132 | return ((( | |
133 | (unsigned long) (year/4 - year/100 + year/400 + 367*mon/12 + day) + | |
134 | year*365 - 719499 | |
135 | )*24 + hour /* now have hours */ | |
136 | )*60 + min /* now have minutes */ | |
137 | )*60 + sec; /* finally seconds */ | |
138 | } | |
139 | ||
068b60a0 | 140 | #endif |