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83d290c5 1// SPDX-License-Identifier: GPL-2.0+
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2/*
3 * (C) Copyright 2001
4 * Wolfgang Denk, DENX Software Engineering, [email protected].
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5 */
6
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7#include <common.h>
8#include <command.h>
199e87c3 9#include <errno.h>
0587dd17 10#include <rtc.h>
18723117 11#include <linux/time.h>
0587dd17 12
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13#define FEBRUARY 2
14#define STARTOFTIME 1970
15#define SECDAY 86400L
16#define SECYR (SECDAY * 365)
17#define leapyear(year) ((year) % 4 == 0)
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18#define days_in_year(a) (leapyear(a) ? 366 : 365)
19#define days_in_month(a) (month_days[(a) - 1])
0587dd17 20
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21static int month_offset[] = {
22 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
23};
24
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25/*
26 * This only works for the Gregorian calendar - i.e. after 1752 (in the UK)
27 */
199e87c3 28int rtc_calc_weekday(struct rtc_time *tm)
0587dd17 29{
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30 int leaps_to_date;
31 int last_year;
0587dd17 32 int day;
0587dd17 33
199e87c3 34 if (tm->tm_year < 1753)
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35 return -1;
36 last_year = tm->tm_year - 1;
0587dd17 37
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38 /* Number of leap corrections to apply up to end of last year */
39 leaps_to_date = last_year / 4 - last_year / 100 + last_year / 400;
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40
41 /*
42 * This year is a leap year if it is divisible by 4 except when it is
43 * divisible by 100 unless it is divisible by 400
44 *
36b898b6 45 * e.g. 1904 was a leap year, 1900 was not, 1996 is, and 2000 is.
0587dd17 46 */
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47 if (tm->tm_year % 4 == 0 &&
48 ((tm->tm_year % 100 != 0) || (tm->tm_year % 400 == 0)) &&
49 tm->tm_mon > 2) {
50 /* We are past Feb. 29 in a leap year */
51 day = 1;
0587dd17 52 } else {
36b898b6 53 day = 0;
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54 }
55
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56 day += last_year * 365 + leaps_to_date + month_offset[tm->tm_mon - 1] +
57 tm->tm_mday;
58 tm->tm_wday = day % 7;
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59
60 return 0;
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61}
62
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63/*
64 * Converts Gregorian date to seconds since 1970-01-01 00:00:00.
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65 * Assumes input in normal date format, i.e. 1980-12-31 23:59:59
66 * => year=1980, mon=12, day=31, hour=23, min=59, sec=59.
67 *
68 * [For the Julian calendar (which was used in Russia before 1917,
69 * Britain & colonies before 1752, anywhere else before 1582,
70 * and is still in use by some communities) leave out the
36b898b6 71 * -year / 100 + year / 400 terms, and add 10.]
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72 *
73 * This algorithm was first published by Gauss (I think).
0587dd17 74 */
90c52423 75time64_t rtc_mktime(const struct rtc_time *tm)
0587dd17 76{
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77 int mon = tm->tm_mon;
78 int year = tm->tm_year;
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79 unsigned long days;
80 time64_t hours;
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81
82 mon -= 2;
90c52423 83 if (0 >= mon) { /* 1..12 -> 11, 12, 1..10 */
36b898b6 84 mon += 12; /* Puts Feb last since it has leap day */
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85 year -= 1;
86 }
87
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88 days = (unsigned long)(year / 4 - year / 100 + year / 400 +
89 367 * mon / 12 + tm->tm_mday) +
90 year * 365 - 719499;
91 hours = days * 24 + tm->tm_hour;
92 return (hours * 60 + tm->tm_min) * 60 + tm->tm_sec;
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93}
94
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95/* for compatibility with linux code */
96time64_t mktime64(const unsigned int year, const unsigned int mon,
97 const unsigned int day, const unsigned int hour,
98 const unsigned int min, const unsigned int sec)
99{
100 struct rtc_time time;
101
102 time.tm_year = year;
103 time.tm_mon = mon;
104 time.tm_mday = day;
105 time.tm_hour = hour;
106 time.tm_min = min;
107 time.tm_sec = sec;
108
90c52423 109 return rtc_mktime((const struct rtc_time *)&time);
18723117 110}
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