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1394f032 BW |
1 | /* |
2 | * File: arch/blackfin/lib/divsi3.S | |
3 | * Based on: | |
4 | * Author: | |
5 | * | |
6 | * Created: | |
7 | * Description: 16 / 32 bit signed division. | |
8 | * Special cases : | |
9 | * 1) If(numerator == 0) | |
10 | * return 0 | |
11 | * 2) If(denominator ==0) | |
12 | * return positive max = 0x7fffffff | |
13 | * 3) If(numerator == denominator) | |
14 | * return 1 | |
15 | * 4) If(denominator ==1) | |
16 | * return numerator | |
17 | * 5) If(denominator == -1) | |
18 | * return -numerator | |
19 | * | |
20 | * Operand : R0 - Numerator (i) | |
21 | * R1 - Denominator (i) | |
22 | * R0 - Quotient (o) | |
23 | * Registers Used : R2-R7,P0-P2 | |
24 | * | |
25 | * Modified: | |
26 | * Copyright 2004-2006 Analog Devices Inc. | |
27 | * | |
28 | * Bugs: Enter bugs at http://blackfin.uclinux.org/ | |
29 | * | |
30 | * This program is free software; you can redistribute it and/or modify | |
31 | * it under the terms of the GNU General Public License as published by | |
32 | * the Free Software Foundation; either version 2 of the License, or | |
33 | * (at your option) any later version. | |
34 | * | |
35 | * This program is distributed in the hope that it will be useful, | |
36 | * but WITHOUT ANY WARRANTY; without even the implied warranty of | |
37 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the | |
38 | * GNU General Public License for more details. | |
39 | * | |
40 | * You should have received a copy of the GNU General Public License | |
41 | * along with this program; if not, see the file COPYING, or write | |
42 | * to the Free Software Foundation, Inc., | |
43 | * 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA | |
44 | */ | |
45 | ||
46 | .global ___divsi3; | |
51be24c3 | 47 | .type ___divsi3, STT_FUNC; |
1394f032 BW |
48 | |
49 | #ifdef CONFIG_ARITHMETIC_OPS_L1 | |
50 | .section .l1.text | |
51 | #else | |
52 | .text | |
53 | #endif | |
54 | ||
55 | .align 2; | |
56 | ___divsi3 : | |
57 | ||
58 | ||
59 | R3 = R0 ^ R1; | |
60 | R0 = ABS R0; | |
61 | ||
62 | CC = V; | |
63 | ||
64 | r3 = rot r3 by -1; | |
65 | r1 = abs r1; /* now both positive, r3.30 means "negate result", | |
66 | ** r3.31 means overflow, add one to result | |
67 | */ | |
68 | cc = r0 < r1; | |
69 | if cc jump .Lret_zero; | |
70 | r2 = r1 >> 15; | |
71 | cc = r2; | |
72 | if cc jump .Lidents; | |
73 | r2 = r1 << 16; | |
74 | cc = r2 <= r0; | |
75 | if cc jump .Lidents; | |
76 | ||
77 | DIVS(R0, R1); | |
78 | DIVQ(R0, R1); | |
79 | DIVQ(R0, R1); | |
80 | DIVQ(R0, R1); | |
81 | DIVQ(R0, R1); | |
82 | DIVQ(R0, R1); | |
83 | DIVQ(R0, R1); | |
84 | DIVQ(R0, R1); | |
85 | DIVQ(R0, R1); | |
86 | DIVQ(R0, R1); | |
87 | DIVQ(R0, R1); | |
88 | DIVQ(R0, R1); | |
89 | DIVQ(R0, R1); | |
90 | DIVQ(R0, R1); | |
91 | DIVQ(R0, R1); | |
92 | DIVQ(R0, R1); | |
93 | DIVQ(R0, R1); | |
94 | ||
95 | R0 = R0.L (Z); | |
96 | r1 = r3 >> 31; /* add overflow issue back in */ | |
97 | r0 = r0 + r1; | |
98 | r1 = -r0; | |
99 | cc = bittst(r3, 30); | |
100 | if cc r0 = r1; | |
101 | RTS; | |
102 | ||
103 | /* Can't use the primitives. Test common identities. | |
104 | ** If the identity is true, return the value in R2. | |
105 | */ | |
106 | ||
107 | .Lidents: | |
108 | CC = R1 == 0; /* check for divide by zero */ | |
109 | IF CC JUMP .Lident_return; | |
110 | ||
111 | CC = R0 == 0; /* check for division of zero */ | |
112 | IF CC JUMP .Lzero_return; | |
113 | ||
114 | CC = R0 == R1; /* check for identical operands */ | |
115 | IF CC JUMP .Lident_return; | |
116 | ||
117 | CC = R1 == 1; /* check for divide by 1 */ | |
118 | IF CC JUMP .Lident_return; | |
119 | ||
120 | R2.L = ONES R1; | |
121 | R2 = R2.L (Z); | |
122 | CC = R2 == 1; | |
123 | IF CC JUMP .Lpower_of_two; | |
124 | ||
125 | /* Identities haven't helped either. | |
126 | ** Perform the full division process. | |
127 | */ | |
128 | ||
129 | P1 = 31; /* Set loop counter */ | |
130 | ||
131 | [--SP] = (R7:5); /* Push registers R5-R7 */ | |
132 | R2 = -R1; | |
133 | [--SP] = R2; | |
134 | R2 = R0 << 1; /* R2 lsw of dividend */ | |
135 | R6 = R0 ^ R1; /* Get sign */ | |
136 | R5 = R6 >> 31; /* Shift sign to LSB */ | |
137 | ||
138 | R0 = 0 ; /* Clear msw partial remainder */ | |
139 | R2 = R2 | R5; /* Shift quotient bit */ | |
140 | R6 = R0 ^ R1; /* Get new quotient bit */ | |
141 | ||
142 | LSETUP(.Llst,.Llend) LC0 = P1; /* Setup loop */ | |
143 | .Llst: R7 = R2 >> 31; /* record copy of carry from R2 */ | |
144 | R2 = R2 << 1; /* Shift 64 bit dividend up by 1 bit */ | |
145 | R0 = R0 << 1 || R5 = [SP]; | |
146 | R0 = R0 | R7; /* and add carry */ | |
147 | CC = R6 < 0; /* Check quotient(AQ) */ | |
148 | /* we might be subtracting divisor (AQ==0) */ | |
149 | IF CC R5 = R1; /* or we might be adding divisor (AQ==1)*/ | |
150 | R0 = R0 + R5; /* do add or subtract, as indicated by AQ */ | |
151 | R6 = R0 ^ R1; /* Generate next quotient bit */ | |
152 | R5 = R6 >> 31; | |
153 | /* Assume AQ==1, shift in zero */ | |
154 | BITTGL(R5,0); /* tweak AQ to be what we want to shift in */ | |
155 | .Llend: R2 = R2 + R5; /* and then set shifted-in value to | |
156 | ** tweaked AQ. | |
157 | */ | |
158 | r1 = r3 >> 31; | |
159 | r2 = r2 + r1; | |
160 | cc = bittst(r3,30); | |
161 | r0 = -r2; | |
162 | if !cc r0 = r2; | |
163 | SP += 4; | |
164 | (R7:5)= [SP++]; /* Pop registers R6-R7 */ | |
165 | RTS; | |
166 | ||
167 | .Lident_return: | |
168 | CC = R1 == 0; /* check for divide by zero => 0x7fffffff */ | |
169 | R2 = -1 (X); | |
170 | R2 >>= 1; | |
171 | IF CC JUMP .Ltrue_ident_return; | |
172 | ||
173 | CC = R0 == R1; /* check for identical operands => 1 */ | |
174 | R2 = 1 (Z); | |
175 | IF CC JUMP .Ltrue_ident_return; | |
176 | ||
177 | R2 = R0; /* assume divide by 1 => numerator */ | |
178 | /*FALLTHRU*/ | |
179 | ||
180 | .Ltrue_ident_return: | |
181 | R0 = R2; /* Return an identity value */ | |
182 | R2 = -R2; | |
183 | CC = bittst(R3,30); | |
184 | IF CC R0 = R2; | |
185 | .Lzero_return: | |
186 | RTS; /* ...including zero */ | |
187 | ||
188 | .Lpower_of_two: | |
189 | /* Y has a single bit set, which means it's a power of two. | |
190 | ** That means we can perform the division just by shifting | |
191 | ** X to the right the appropriate number of bits | |
192 | */ | |
193 | ||
194 | /* signbits returns the number of sign bits, minus one. | |
195 | ** 1=>30, 2=>29, ..., 0x40000000=>0. Which means we need | |
196 | ** to shift right n-signbits spaces. It also means 0x80000000 | |
197 | ** is a special case, because that *also* gives a signbits of 0 | |
198 | */ | |
199 | ||
200 | R2 = R0 >> 31; | |
201 | CC = R1 < 0; | |
202 | IF CC JUMP .Ltrue_ident_return; | |
203 | ||
204 | R1.l = SIGNBITS R1; | |
205 | R1 = R1.L (Z); | |
206 | R1 += -30; | |
207 | R0 = LSHIFT R0 by R1.L; | |
208 | r1 = r3 >> 31; | |
209 | r0 = r0 + r1; | |
210 | R2 = -R0; // negate result if necessary | |
211 | CC = bittst(R3,30); | |
212 | IF CC R0 = R2; | |
213 | RTS; | |
214 | ||
215 | .Lret_zero: | |
216 | R0 = 0; | |
217 | RTS; | |
51be24c3 MF |
218 | |
219 | .size ___divsi3, .-___divsi3 |